Groups HT23, Normal subgroups


Flashcards

@Define a normal subgroup $H$ of $G$.

$H \trianglelefteq G$ if

\[gH = Hg\]

for all $g \in G$, or equivalently

\[g^{-1}hg \in H\]

for all $g \in G$, $h \in H$.

@Define a simple group.

A group where $G$ and $\{e _ G\}$ are the only normal subgroups.

Given that $H$ will be a normal subgroup of $G$ if and only if

\[g^{-1}hg \in H\]

for all $g \in G$, $h \in H$, what does this mean in terms of conjugacy classes?

$H$ consists of the union of a number of conjugacy classes.

Can you give an example of a non-Abelian simple group?

\[A _ 5\]

Let $H \leqslant G$. What fact about the index of $H$ in $G$ allows you to conclude $H$ is a normal subgroup?

\[ \vert G/H \vert = 2\]

What is special about the subgroup formed by the kernel of any homomorphism?

It is a normal subgroup.

Let $G$ be a group. @Define the centre of $G$, denoted $Z(G)$.

\[\{g \in G : gh = hg \text{ } \forall h \in G\}\]

What is always true about the relationship between centre of a group $Z(G)$ and the group itself?

\[Z(G) \trianglelefteq G\]

normal subgroup

Other than showing that $gH = Hg$ or that $g^{-1}hg \in H$ for all $g$, what’s an alternative way that you could show $H$ is a normal subgroup of some group?

Show it’s the kernel of a homomorphism.

When asked to find the centre of a group, e.g. of $D _ 8$, what can you use to do this rather than considering everything invariant under conjugation?

Consider trivial conjugacy classes, i.e. $r^2$.

Proofs