Further Maths - Cubics


Here, using z instead of x means that the variable is complex. w is also sometimes used.

The first step is to find the one real solution. Since it’s a cubic, there will be three solutions and by examining the graph you can see that there always must be at least one real solution (cubics always cross the y-axis at least once).

For z=1:

z3+9z2+33z+2513+9×12+33×1+250

For z=1:

(1)3+9×(1)2+33×1+25=01+933+25=0

So we have one bracket, (z+1). We can now write out the cubic like so:

(z+1)(Az2+Bz+C)

We can work out A,Band,C by inspection:

  • A must be 1 since the final result of multiplying everything out has a



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