Further Maths - Numerical Methods


See Also

Try out an interactive visualisation of Euler’s method here: Euler’s method.

Flashcards

2021-12-08

How could you summarise Euler’s method for solving first-order differential equations?


Start with some point on the curve and then follow the direction of the curve.

If a gradient is given by $\frac{\text{d}y}{\text{d}x}$, how much would you increase the $y$-coordinate for a step size of $h$?


\[y_1 = y_0 + \frac{\text{d}y}{\text{d}x} h\]
What does using the assumption
\[\left( \frac{\text{d}y}{\text{d}x} \right) _ 0 \approx \frac{y _ 1 - y _ 0}{h}\]

mean you should do in a question?? Use Euler’s method.

What assumption are you making for Euler’s method?


\[\left( \frac{\text{d}y}{\text{d}x} \right)_0 \approx \frac{y_1 - y_0}{h}\]

What is the formula for $y _ {r + 1}$ given $\frac{\text{d}y}{\text{d}x}$ and $y _ r$ using Euler’s method?


\[y_{r + 1} = y_r + \left( \frac{\text{d}y}{\text{d}x} \right)h\]

If you were asked to use $5$ iterations to approximate a solution at $x = 2$ given the point $(1, 2)$ using Euler’s method, what would your step size be?


\[h = 0.2\]
What does using the assumption
\[\left( \frac{\text{d}y}{\text{d}x} \right) _ 0 \approx \frac{y _ 1 - y{-1}}{2h}\]

mean you should do in a question?? Use the midpoint method.

What is the improvement on Euler’s method called?


The midpoint method.

What assumption are you making for the midpoint method?


\[\left( \frac{\text{d}y}{\text{d}x} \right)_0 \approx \frac{y_1 - y{-1}}{2h}\]

What is the formula for $y _ {r+1}$ in terms of $y _ r$ and $y _ {r-1}$ using the midpoint method?


\[y_{r+1} \approx y_{r-1} + 2h\left(\frac{\text{d}y}{\text{d}x}\right)_{y_r}\]

What do you often need to do in order to use the midpoint method and given one point?


Use Euler’s method to find the next point.

What’s a nice way of answering numerical method questions?


Using a table.

2021-12-10

What assumption are you making for approximating solutions to second order differential equations?


\[(\frac{\text{d}^2y}{\text{d}x^2})_{0} \approx \frac{\left(\frac{\text{d}x}{\text{d}y}\right)_0 - \left(\frac{\text{d}x}{\text{d}y}\right)_{-1}}{h}\]

#####

\[(\frac{\text{d}^2y}{\text{d}x^2}) _ {0} \approx \frac{\left(\frac{\text{d}x}{\text{d}y}\right) _ 0 - \left(\frac{\text{d}x}{\text{d}y}\right) _ {-1}}{h}\]

What is this assumption in terms of $y _ 1$, $y _ 0$ and $y _ {-1}$??

\[(\frac{\text{d}^2y}{\text{d}x^2})_{0} \approx \frac{y_1 - 2y_0 + y_{-1}}{h^2}\]
What’s the formula for $y _ {r+1}$ in terms of $y _ r$ and $y _ {r-1}$ using the approximation
\[(\frac{\text{d}^2y}{\text{d}x^2})_{0} \approx \frac{y_1 - 2y_0 + y_{-1}}{h^2}??\]

y_{r + 1} \approx 2y_4 - y_{r-1} + h^2(\frac{\text{d}^2y}{\text{d}x^2})_{r}

\[<details class="flashcard"> <summary class="flashcard-front"><p>When do you have to use simultaneous equations when approximating a second-order differential equation?</p> </summary> <hr> <div class="flashcard-back"> <p>When they ask you to use the midpoint method.</p> </div> </details> <details class="flashcard"> <summary class="flashcard-front"><p>What is Simpson’s rule used for?</p> </summary> <hr> <div class="flashcard-back"> <p>Approximating integrals.</p> </div> </details> <details class="flashcard"> <summary class="flashcard-front"><p>How does Simpson’s rule work?</p> </summary> <hr> <div class="flashcard-back"> <p>Splitting curves up into quadratics.</p> </div> </details>##### What is Simpson's rule for\]

\int^b_a f(x) dx

\[in terms of even values, odd values and endpoints??\]

\int^b_a f(x) dx \approx \frac{1}{3}h((\text{endpoints}) + 4(\text{odd values}) + 2(\text{even values}))

$$

Why can’t you use Simpson’s rule when splitting up a curve into 7 strips/intervals?


Simpson’s rule only works with an even number of strips/intervals.

2022-04-24

What’s a stupid mnemonic for remembering Simpson’s rule?


On the third of Haugust, it’s the end 4 Mr Odd. He was 2 even.

“On the third of Haugust, it’s the end 4 Mr Odd. He was 2 even.” Can you turn this into Simpson’s rule?


\[\frac{1}{3} h (\text{end} + 4\text{odd} + 2\text{even})\]



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