# MAT - Paper 2008 - Q2

## Flashcards

### 2021-10-13

You’ve rearranged an expression to get

\[(8 - 2a^2)x^2 + (24 - 4ab)xy + (18-2b^2)y^2 = 0\]
What must now be true for it to always equal zero for positive integers $x$ and $y$?

\[2a^2 = 8\]
\[4ab = 24\]
\[2b^2 = 18\]