Quantum Information HT24, Basic measurements


Flashcards

What does it mean for two orthonormal bases $\{ \vert \psi _ n \rangle : n = 0, \cdots, d-1\}$ and $\{ \vert \psi _ n’ \rangle : n = 0, \cdots, d-1\}$ to be equal up to global phase?


For each $n$, $\exists \gamma _ n \in [0, 2\pi]$ such that

\[\vert \psi' _ n \rangle = e^{i\gamma _ n} \vert \psi _ n \rangle\]

What are the possible types of basic measurements on a $d$-dimensional quantum system?


Orthonormal bases in $\mathbb C^d$, up to global phases.

Suppose:

  • We have a quantum system in a state $ \vert \psi \rangle$
  • We perform the basic measurement corresponding to the orthonormal basis $\{ \vert \psi _ k \rangle : k = 0, \cdots, d-1\}$.

What is the probability we obtain the outcome $ \vert \psi _ k\rangle$, and what is the state of the system immediately after the measurement?


\[p _ k = \vert \langle \psi _ k \vert \psi\rangle \vert ^2\]

If we obtain the outcome $\psi _ l$, the state of the system immediately after the measurement is $ \vert \psi _ n\rangle$.

Can you state the Born rule?


Suppose:

  • We have a quantum system in a state $ \vert \psi \rangle$
  • We perform the basic measurement corresponding to the orthonormal basis $\{ \vert \psi _ k \rangle : k = 0, \cdots, d-1\}$.

Then the probability we obtain the outcome $ \vert \psi _ k\rangle$ is

\[p _ k = \vert \langle \psi _ k \vert \psi\rangle \vert ^2\]

Suppose $\{ \vert \psi _ n \rangle : n = 0, \cdots, d-1\}$ and $\{ \vert \psi _ n’ \rangle : n = 0, \cdots, d-1\}$ are orthonormal bases equal up to global phase. What can we say about the probabilities of obtaining each outcome $\psi _ k$ and $\psi’ _ k$, and the post-measurement state?


The probabilities are the same

\[\vert \langle \psi _ n \vert \psi\rangle \vert ^2 = \vert \langle \psi' _ n \vert \psi \rangle \vert ^2\]

and the post-measurement state will always be the same.

What is the computational basis for $\mathbb C^d$?


The orthonormal basis given by

\[\\{ \vert k \rangle : k = 0, \cdots, d - 1\\}\]

What is the Fourier basis for $\mathbb C^d$?


The orthonormal basis given by

\[\vert e _ k \rangle := \frac{1}{\sqrt d} \sum^{d-1} _ {m=0} \exp\left[ \frac{2\pi i m k}{d} \right] \vert m\rangle\]

Can you define the vectors $ \vert +\rangle$ and $ \vert -\rangle$, and how do these relate to the Fourier basis?


\[\begin{aligned} \vert +\rangle &:= \frac{ \vert 0\rangle + \vert 1\rangle}{\sqrt 2} \\\\ \vert -\rangle &:= \frac{ \vert 0\rangle - \vert 1\rangle}{\sqrt 2} \\\\ \end{aligned}\]

These are the Fourier basis vectors in dimension $2$.

Suppose we have the ONB $\{ \vert \phi _ 0\rangle, \vert \phi _ 1\rangle, \vert \phi _ 2\rangle\}$ where

\[\begin{aligned} \vert \phi _ 0 \rangle &:= \frac{1}{\sqrt 2} ( \vert 0\rangle + i \vert 2\rangle) \\\\ \vert \phi _ 1 \rangle &:= \vert 1\rangle \\\\ \vert \phi _ 2 \rangle &:= \frac{1}{\sqrt 2} ( \vert 0\rangle - i \vert 2\rangle) \end{aligned}\]

What state gives rise to the following probability distribution

\[\begin{aligned} p(0) &= 1 / 5 \\\\ p(1) &= 1 /3 \\\\ p(2) &= 7/15 \end{aligned}\]

for each of the outcomes?


Use the ONB and give coefficients that are square roots of the corresponding amplitudes, so

\[\vert \psi\rangle = \sqrt{1/5} \vert \phi _ 0\rangle + \sqrt{1/3} \vert \phi _ 1\rangle + \sqrt{7/15} \vert \phi _ 2\rangle\]

Proofs




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