Analysis I MT22, Algebra of limits
Flashcards
What are the two ingredients to proving that if $a _ n \to a$ and $b _ n \to b$ then $\frac{a _ n}{b _ n} \to \frac{a}{b}$?
- Proving the product law for limits, $a _ n b _ n \to a b$
- Proving the reciprocal law for limits, $\frac{1}{b _ n} \to b _ n$.
When proving the reciprocal law for limits, i.e. that $\frac{1}{b _ n} \to \frac{1}{b}$, what two values of epsilon do you take, to show that $ \vert b _ n - b \vert $ can be less than?
- $\frac{ \vert b \vert }{2}$
- $\frac{ \vert b \vert ^2}{2}\epsilon$
When proving the reciprocal law for limits, i.e. that $\frac{1}{b _ n} \to \frac{1}{b}$, what do you rearrange $\left \vert \frac{1}{b _ n} - \frac{1}{b}\right \vert $ into?
When proving the reciprocal law for limits, i.e. that $\frac{1}{b _ n} \to \frac{1}{b}$, one of the aims is to show that $\frac{1}{ \vert b _ n \vert } < \frac{2}{ \vert b \vert }$. You know that $ \vert b _ n - b \vert < \frac{ \vert b \vert }{2}$, from the definition of convergence of $b _ n$. Starting from $ \vert b \vert $, how do you use this to show $\frac{1}{ \vert b _ n \vert } < \frac{2}{ \vert b \vert }$?
which then implies $\frac{ \vert b \vert }{2} < \vert b _ n \vert $ and then taking reciprocals gives the required result.
When proving the product law for limits, i.e. that $a _ n b _ n \to ab$, what magic do you to $ \vert a _ n b _ n - ab \vert $ in order to get it into “a form you control”?
When proving the product law for limits, i.e. that $a _ n b _ n \to ab$, what important theorem do you make use of?
Any convergent series is bounded.