Physics - Collisions in 2D

What is the formula for the vertical component of a momentum $p$ ?

p \sin θ

What is the formula for the horizontal component of a momentum $p$ ?

p \cos θ

If an object with mass $m_{1}$ is travelling in a straight line with velocity $v_{1}$ , what is its momentum?

m_{1} v_{1}

If an object with mass $m_{1}$ is travelling at an angle $θ_{1}$ to the $x$ direction with velocity $v_{2}$ , what is its momentum?

m_{1} v_{1} \cos θ_{1}

What is true about $θ_{1}$ and $θ_{2}$ for two identical masses in a 2D collision?

θ_{1} + θ_{2} = 90^{\circ}

If two objects have the same mass, what angle do they make with each other in a 2D collision?

90^{\circ}

What is true about momentum in a 2D collision?

It is conserved in both the $x$ and $y$ directions.

How are collisions in 2D similar to projectiles?

You treat the horizontal and vertical components seperately.

What is the vertical component of momentum for an object moving only in the $x$ direction?

0

After a collision, one object has mass $m_{1}$ and velocity $v_{2}$ at an angle of $θ_{1}$ . The other object has a mass $m_{2}$ and velocity $v_{3}$ . What is the horizontal component of momentum after the collision?

m_{1} v_{2} \cos θ_{1} + m_{2} v_{3} \cos θ_{2}

After a collision, one object has mass $m_{1}$ and velocity $v_{2}$ at an angle of $θ_{1}$ . The other object has a mass $m_{2}$ and velocity $v_{3}$ . What is the vertical component of momentum after the collision?

m_{1} v_{2} \sin θ_{1} + m_{2} v_{3} \sin θ_{2}

#####

m_{1} v_{2} \sin θ_{1} + m_{2} v_{3} \sin θ_{2} = 0

How could you rewrite this??

m_{1} m_{2} \sin θ_{1} = - m_{2} v_{3} \sin θ_{2}

Related posts