Physics - Stopping Distances


What is the formula for stopping distances?


\[\text{stopping distance} = \text{thinking distance} + \text{braking distance}\]

What affects reaction time in the context of stopping distances?


  • Tiredness
  • Alcohol
  • Drugs
  • Other passengers

What are the two factors that affect stopping distance?


  • Reaction time
  • Speed of the vehicle

Assuming a constant velocity ($v$) during reaction time, what is the formula for thinking distance?


\[s = vt\]

What are the three factors that affect braking distance?


  • Breaking force
  • Mass of vehicle
  • Velocity

What things can affect the breaking force?


  • Break conditions
  • Tire conditions
  • Road conditions

A larger vehicle mass has what affect on braking distance?


A larger breaking distance.

When a car is in motion, what’s the kinetic energy of the car?


\[\frac{1}{2} m v^2\]

Where is the kinetic energy of a car transferred to when braking?


Transferred to the thermal store of the breaks and the surroundings.

What is the work done by a car when it’s breaking?


\[W = F \times s\]

When a car is breaking and the energy is being calculated by $W = F \times s$, what does $F$ represent?


The breaking force of the car.

What are the units for work done?


joules, $J$

What must be true about the kinetic energy of a car and the work done when breaking?


They must be equal.

What is the formula for the kinetic energy of a car in relation to work done?


\[\frac{1}{2} m v^2 = F \times s\]

What is the formula for breaking distance involving mass, velocity and breaking force?


\[\frac{1}{2} m v^2 = F \times s\]

What is the formula for breaking distance involving velocity and acceleration?


\[\text{breaking distance} = \frac{(initial velocity)^2}{2 \times \text{acceleration}}\]

What does a $2\times$ initial velocity translate to in terms of breaking distance?


$4\times$ the breaking distance.

The breaking distance equation involving velocity and acceleration is a special case of which SUVAT equation?


\[v^2 = u^2 + 2as\]

If a truck is exerts a breaking force of $8700N$ and has a mass of $2300kg$, how could you calculate the acceleration?


\[\text{8700N}{2300kg} \\\\ F = ma\]



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