The Most Important Proofs in Prelims Algebra


Linear Algebra I

Steinitz exchange lemma

  • Consider two different ways of writing a vector in the span
  • Can just rearrange both

The dimension formula

  • i.e. $\dim(U \cap W) + \dim(U + W) = \dim(U) + \dim(W)$
  • Consider a basis of $V \cap W$ and then seperately extend to a basis of $V$ and $W$.
  • Then show that the basis with both extensions is a basis of $V+W$.
  • Can show it’s spanning, but to show it’s linearly independent you need to note that any vector in $U + W$ must also be in $U \cap W$ by rearranging both sides of the equation.
  • Then linear independence follows from the linear independence of the other two bases.

The rank-nullity theorem

  • Consider a basis for kernel, extend to a basis of the input vector space.
  • Then show that the non-kernel bits of the input vector space form a basis for the image.

Change of basis theorem ($\ast$)

  • Apply definitions. Consider $U, V, W$ as finite-dimensional vector spaces with ordered bases $\mathcal{U, V, W}$. Then write each $S(u _ i)$ or $T(v _ i)$ as a sum.
  • Rearrange sum to notice the hidden matrix multiplication and then result follows.

Row rank and column rank are equal

  • Make the long line of equalities $\text{rowrank(A) = rowrank(R) = colrank(R) = colrank(A)}$.
  • First equality comes from fiddling around with the definition, and using the fact that if $A = ER$ then $E$ is invertible.
  • Second equality comes from considering non-zero rows and columns in the RREF.
  • Final equality comes from a combination of two things: noting that the kernel of both $A$ and $R$ must be the same and then using the rank-nullity theorem.

Cauchy-Schwarz inequality

  • All follows from expression $\langle v + tw, v + tw \rangle$. This must be positive as it’s an inner product, and then you get a quadratic in $t$ that you take the discriminant of.
  • For equality, it must be the case that $\langle v + tw, v + tw\rangle = 0$, which implies $ \vert \vert v + tw \vert \vert = 0$, which itself means that $v = -tw$, and so they are linearly dependent.

Rank and nullity of composition of linear maps ($\ast$)

Linear Algebra II

Multiplicativity of determinant

  • Show that the determinant is multiplicative with respect to elementary row operations
  • Then any matrix can be written as a product of elementary row operations

Eigenvectors are linearly independent

  • Argue by contradiction, consider a minimum set of linearly dependent and then apply a transformation to both sides that keeps them as zero.

Geometric multiplicity less than algebraic multiplicity

  • Maybe worth going over at least once again.
  • Consider the matrix with respect to the basis beginning with the basis for its eigenspace beginning with that particular eigenvalue.

Symmetric matrices have real eigenvalues

  • Rearrange something in two different ways

Symmetric matrices are diagonalisable (Spectral theorem)

  • Went over recently
  • Quite involved, with lots of magically constructing things
  • But main idea is by induction on the dimension of the matrix
  • Since you know that the block matrix inside $P^\intercal A P$ will also be real symmetric

Groups I

Permutations as products of disjoint cycles

  • Explain that you can tackle a cycle at a time by exhausting all particular elements of that cycle.

Order of permutation is LCM of cycle types

  • One of the proofs where you show $o(g) = L$ by $o(g) \vert L$ and $L \vert o(g)$.
  • Made a lot easier by clean notation: let $\pi$ be the permutation, and say it consists of disjoint cycles $s _ 1, \ldots, s _ r$ with orders $k _ 1, \ldots, k _ r$.

Conjugate iff same cycle type ($\ast$)

  • Forward: note that the conjugation is distributive over the disjoint cycles
  • Backward: set up a permutation between each disjoint cycle

Subgroups of cyclic groups are cyclic

  • Follows from defining $n = \min{k > 0 : g^k \in H}$ and then for any $g^a \in H$, considering $a = qn + r$, and rearranging to see that $r = 0$.

Chinese remainder theorem

  • Consider the order of the generator $(g, h)$ where $g$ and $h$ are generators for $C _ m$ and $C _ n$ respectively.
  • Then show $k \vert mn$ and $mn \vert k$, using Bezout’s lemma for the last step.

Equivalence classes form a partition

  • Partitions are a collection of disjoint sets whose union is the entire set.
  • Show equivalence classes satisfy this definition.

Coset equality lemma

  • [[Notes - Groups HT23, Cosets]]U
  • Suppose $u \in gH = kH$. Write in two different ways, and you end up getting something like $gh _ 1 = kh _ 2$ which implies the forward direction.
  • For the backward direction, note that then $k = gh$, so $kH = g(hH) = gH$.

Lagrange’s theorem

  • [[Notes - Groups HT23, Lagrange’s theorem]]U
  • Consider the equivalence relation given by two elements having the same left coset.
  • Can show this is a partition by showing that if two left cosets are not disjoint, then they are the same.
  • Finally need to show each coset has the same number of elements as $ \vert H \vert $. Can do this by showing that $h \mapsto gh$ is a bijection.

Fermat’s theorem

  • Just the size of the multiplicative group, a consequence of Lagrange’s theorem

Euler’s theorem

  • Just the size of the multiplicative group, another consequence of Lagrange’s theorem

Every group with even order has element of order 2

  • Consider pairing up elements with their inverses

Groups II

Kernel of a homomorphism is a normal subgroup

Equivalence in normal subgroup definition

  • What did I mean by this??

First isomorphism theorem

Orbits form a partition

Orbit-stabilizer theorem

  • Consider bijection between $G/\text{Stab}(x)$ and $\text{Orb}(x)$ given by $g \text{Stab}(x) \mapsto g \cdot x$. Surjective as we can pick any $g$, and then injective by considering the coset equality lemma.

Orbit counting formula

  • [[Notes - Groups TT23, Counting orbits]]U
  • Consider $A = \{(g, s): g \cdot s = s\}$.
  • Two different ways of summing it up, either over $g \in G$ or over $s \in S$.
  • The $s \in S$ way can be manipulated in order to make it talk about orbits, and then you set the two equal to eachother.

Left actions and homomorphisms to symmetry groups are samish

Cauchy’s theorem

Cayley’s theorem

  • Apply the above theorem to $G$ acting on itself by left multiplication.



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