Stats - Binomial Distribution


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Flashcards

What $ \left(\begin{matrix} n \ r \end{matrix}\right) $ could you write for the number of ways you can pick $3$ students from a class of $28$?


\[\left(\begin{matrix} 28 \\\\ 3 \end{matrix}\right)\]
What $ \left(\begin{matrix} n \ r \end{matrix}\right) $ could you write for the number of ways you could pick $2$ left-handed people from a total of $3$ people?
\[\left(\begin{matrix} 3 \\\\ 2 \end{matrix}\right)\]

What $ \left(\begin{matrix} n \ r \end{matrix}\right) $ could you write for the number of ways you could pick $1$ defective screw out of $20$ defective screws?


\[\left(\begin{matrix} 20 \\\\ 1 \end{matrix}\right)\]

In a group of three people, two are left-handed and one is not. The probability of being left-handed is $0.1$, so the probability of being right-handed is $0.9$. What is the probability for each permutation?


\[0.1 \times 0.1 \times 0.9\]

In a group of three people, two are left-handed and one is not. The probability of being left-handed is $0.1$, so the probability of being right-handed is $0.9$. What $ \left(\begin{matrix} n \ r \end{matrix}\right) $ could you write for the number of outcomes?


\[\left(\begin{matrix} 3 \\\\ 2 \end{matrix}\right)\]

In a group of three people, two are left-handed and one is not. The probability of being left-handed is $0.1$, so the probability of being right-handed is $0.9$. There are $ \left(\begin{matrix} 3 \ 2 \end{matrix}\right) $ possible outcomes and the probability of each one is $0.1 \times 0.1 \times 0.9$. How could you write for the overall probability?


\[\left(\begin{matrix} 3 \\\\ 2 \end{matrix}\right) \times 0.1 \times 0.1 \times 0.9\]
\[X ~ B(n, p)\]

What does this mean?


$X$ has a binomial distribution with $n$ trials and probability of success $p$.

What are the 4 criteria for $X$ being modelled with a binomial distribution?


  1. There are a fixed number of trials
  2. There are two possible outcomes
  3. There is a fixed probability of success
  4. The trials are independent of each other

What is the formula for $P(X = r)$ if $X ~ B(n, p)$?


\[\left( \begin{matrix}n \\\\ r\end{matrix} \right) p^r(1-p)^{n-r}\]
\[P(X = r) = \left( \begin{matrix}n \\\\ r\end{matrix} \right) p^r(1-p)^{n-r}\]

What does $r$ represent?


The number of successes.

\[P(X = r) = \left( \begin{matrix}n \\\\ r\end{matrix} \right) p^r(1-p)^{n-r}\]

What does $n$ represent?


The number of trials.

\[P(X = r) = \left( \begin{matrix}n \\\\ r\end{matrix} \right) p^r(1-p)^{n-r}\]

What does $p$ represent?


The probability of success.

\[P(X = r) = \left( \begin{matrix}n \\\\ r\end{matrix} \right) p^r(1-p)^{n-r}\]

If $p^r$ is the probability of $r$ successes and $(1-p)^{n-r}$ is the probability of the number of failures, can you explain $p^r(1 - p)^{n - r}?


It’s the probability that each outcome is true.

\[P(X = r) = \left( \begin{matrix}n \\\\ r\end{matrix} \right) p^r(1-p)^{n-r}\]

If $p^r$ is the probability of $r$ successes, can you explain $n - r$?


If there are $r$ successes out of $n$, then $n - r$ must be the number of failures.

#####

\[P(X = r) = \left( \begin{matrix}n \\\\ r\end{matrix} \right) p^r(1-p)^{n-r}\]

If $p$ is the probability of success, can you explain $(1 - p)$? In a binomial distribution there are only two outcomes, so $(1 - p)$ is the probability of failure.

Why can’t use you use the binomial distribution to model an experiment where you have red counters and green counters in a bag and you wish to find the probability that removing $5$ counters would contain $3$ greens?


Because the trials aren’t independent of each other.

\[P(X = 0)\]

What is this equal to if $X ~ B(n, p)$?


\[(1 - p)^n\]
\[P(X = 0)\]

If $X ~ B(n, p)$, what does this mean in simple terms?


The probability of no successes.

\[P(X = n)\]

What is this equal to if $X ~ B(n, p)$?


\[p^n\]
\[P(X = n)\]

If $X ~ B(n, p)$, what does this mean in simple terms?


The probability of no failures.

On a Classwiz calculator, how can you work out $P(X = r)$ if $X ~ B(n, p)$?


  • Distribution
  • Binomial PD
  • Variable
  • Enter values for $x$, $n$ and $p$.

On a Classwiz calculator, how can you work out $P(X \le r)$ if $X ~ B(n, p)$?


  • Distribution
  • Down, Binomial CD
  • Variable
  • Enter values for $x$, $n$ and $p$.

2021-02-09

\[P(X \le 1)\]

What’s the long-winded way of working this out?


\[P(X = 0) + P(X = 1)\]
\[P(X \le 6)\]

What’s the long-winded way of working this out?


\[P(X = 0) + P(X = 1) + P(X = 2) + ...\]
\[P(X > 5)\]

How could you rewrite this so it can be used with a binomial cumulative distribution?


\[1 - P(X \le 5)\]
\[P(X \ge 7)\]

How could you rewrite this so it can be used with a binomial cumulative distribution?


\[1 - P(X \le 6)\]
\[P(X < 10)\]

How could you rewrite this so it can be used with a binomial cumulative distribution?


\[P(X \le 9)\]
\[P(X > 16)\]

How could you rewrite this so it can be used with a binomial cumulative distribution?


\[1 - P(X \le 16)\]
\[P(6 < X \le 10)\]

How could you rewrite this so it can be used with a binomial cumulative distribution?


\[P(X \le 10) - P(X \le 6)\]
\[P(\text{"at most 8"})\]

How could you rewrite this so it can be used with a binomial cumulative distribution?


\[P(X \le 8)\]
\[P(\text{"no more than 3"})\]

How could you rewrite this so it can be used with a binomial cumulative distribution?


\[P(X \le 3)\]



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