Lecture - Groups TT23, Cayley’s theorem
Flashcards
ObstNaLP0ACpKhAyIdlJ54wiWhat theorem establishes a correspondence between actions and homomorphisms?
Given a left action of a group $G$ on $S$, then there is an associated homomorphism \(\rho : G \to \text{Sym}(S)\) and likewise for each homomorphism $\rho : G \to \text{Sym}(S)$ there is an associated left action of $G$ on $S$.
Obs1AlpunXCZ6rz8iSmc1OACIf you have a homomorphism $\rho : G \to \text{Sym}(S)$, how can you construct a group action (there’s no need to prove this is a group action)?
ObsEAzDlgjno8GrL4KOgqHt7If you have a left action $\langle\cdot\rangle$ can you give an associated homomorphism (there’s no need to prove this a homomorphism)?
ObsgjS2qDZPHODBIiDp7qML7Can you state Cayley’s theorem?
Every finite group is isomorphic to a subgroup of a permutation group $S _ n$ for some $n$.
ObsXMNqQPe0RyjreoCLLNqfEQuickly justify that the map given by $G \to \text{Sym}(S)$ given by
\(\rho (g) = (x \mapsto g \cdot x)\)
is a homomorphism.
ObsMlcBRxawyXTXNKsFNSRmSQuickly justify that there’s a valid left action given by $g \cdot x = \rho(g)(x)$ where $\rho$ is a homomorphism $\rho : G \to \text{Sym}(S)$.
\(e \cdot x = \rho(e)(x) = \text{id}(x) = x\) and \(g \cdot (h \cdot x) = \rho(g)(h \cdot x) = \rho(g)(\rho(h)(x)) = (\rho(g) \circ \rho(h) )(x) = \rho(gh)(x) = gh \cdot x\)
Proofs
Obs00o2JQ3kPKCdRM41kSb25Prove that, if you are given a left action of a group $G$ on $S$, then there is an associated homomorphism
\(\rho : G \to \text{Sym}(S)\)
and likewise for each homomorphism $\rho : G \to \text{Sym}(S)$ there is an associated left action of $G$ on $S$.
Todo (groups, page 83).
Obs8Kp71kyjU0tPcjC8y3XrGProve (by appealing to the theorem that links left actions and homomorphisms) Cayley’s theorem:
Every finite group is isomorphic to a subgroup of a permutation group $S _ n$ for some $n$.
Every finite group is isomorphic to a subgroup of a permutation group $S _ n$ for some $n$.
Todo.