Lecture - Groups TT23, Cayley’s theorem


Flashcards

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What theorem establishes a correspondence between actions and homomorphisms?


Given a left action of a group $G$ on $S$, then there is an associated homomorphism \(\rho : G \to \text{Sym}(S)\) and likewise for each homomorphism $\rho : G \to \text{Sym}(S)$ there is an associated left action of $G$ on $S$.

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If you have a homomorphism $\rho : G \to \text{Sym}(S)$, how can you construct a group action (there’s no need to prove this is a group action)?


\[g \cdot s = (\rho(g))(s)\]
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If you have a left action $\langle\cdot\rangle$ can you give an associated homomorphism (there’s no need to prove this a homomorphism)?


\[\rho(g) = (x \mapsto g \cdot x)\]
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Can you state Cayley’s theorem?


Every finite group is isomorphic to a subgroup of a permutation group $S _ n$ for some $n$.

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Quickly justify that the map given by $G \to \text{Sym}(S)$ given by \(\rho (g) = (x \mapsto g \cdot x)\) is a homomorphism.


\[\rho(gh) = (x \mapsto gh \cdot x) = (y \mapsto g \cdot y) \circ (x \mapsto h \cdot x) = \rho(g) \circ \rho(h)\]
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Quickly justify that there’s a valid left action given by $g \cdot x = \rho(g)(x)$ where $\rho$ is a homomorphism $\rho : G \to \text{Sym}(S)$.


\(e \cdot x = \rho(e)(x) = \text{id}(x) = x\) and \(g \cdot (h \cdot x) = \rho(g)(h \cdot x) = \rho(g)(\rho(h)(x)) = (\rho(g) \circ \rho(h) )(x) = \rho(gh)(x) = gh \cdot x\)

Proofs

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Prove that, if you are given a left action of a group $G$ on $S$, then there is an associated homomorphism \(\rho : G \to \text{Sym}(S)\) and likewise for each homomorphism $\rho : G \to \text{Sym}(S)$ there is an associated left action of $G$ on $S$.


Todo (groups, page 83).

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Prove (by appealing to the theorem that links left actions and homomorphisms) Cayley’s theorem:

Every finite group is isomorphic to a subgroup of a permutation group $S _ n$ for some $n$.


Todo.




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